Given : Fe2+(aq)+2e−→Fe(s); E⊖=−0.44V Al3++3e−→Al(s); E⊖=−1.66V Br2+2e−→2Br⊖(aq); E⊖=−1.08V The decreasing order of reducing power is:
A
Fe>Al>Br⊖
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B
Al>Fe>Br⊖
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C
Br⊖>Fe>Al
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D
Fe>Br⊖>Al
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Solution
The correct option is DAl>Fe>Br⊖ (Al>Fe>Br⊖) More the oxidation potential, more the reducing power. ∴E⊖oxid(Al|Al3+)(+1.66C)>E⊖oxid(Fe|Fe2+)(0.044V)>E⊖oxid(2Br⊖|Br2)(−1.08V) hence, the decreasing order of reducing power Al>Fe>Br⊖