Given - Fe2- aq - 2e- Fes- E- - -0-44 V Al3- - 3e- Als- E- - -1-66 V Br2- 2e- 2Br- aq- E- - -1-08 VThe decreasing order of reducing power is-

The correct option is D Al gt; Fe gt; Br^⊖ (Al gt; Fe gt; Br^⊖) More the oxidation potential, more the reducing power. ∴ E^⊖_oxid (Al ...

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Secondary Cells

Given : Fe2+...

Question

Given :
$F e^{2 +} (a q) + 2 e^{-} \to F e (s)$ ; $E^{⊖} = - 0.44 V$
$A l^{3 +} + 3 e^{-} \to A l (s)$ ; $E^{⊖} = - 1.66 V$
$B r^{2 +} 2 e^{-} \to 2 B r^{⊖} (a q)$ ; $E^{⊖} = - 1.08 V$
The decreasing order of reducing power is:

F e > A l > B r^{⊖}

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A l > F e > B r^{⊖}

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B r^{⊖} > F e > A l

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F e > B r^{⊖} > A l

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Solution

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F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q); E^{\circ} = + 0.77 V

A l^{3 +} (a q) + 3 e^{-} \to A l (s); E^{\circ} = - 1.66 V

B r_{2} (a q) + 2 e^{-} \to 2 B r^{-}; E^{\circ} = + 1.09 V

F e^{3 +} (a q) + e \to F e^{2 +} (a q); E^{o} = + 0.77 V

A l^{3 +} (a q) + 3 e \to A l (s); E^{o} = - 1.66 V

B r_{2} (a q) + 2 e \to 2 B^{-} (a q); E^{o} = + 1.08 V

F e

A g^{+} (a q) + e^{-} - > A g (s) E^{\circ} = + 0.80 V

C u^{2 +} (a q) + 2 e^{-} - - > C u (s) E^{\circ} = + 0.34 V

P b^{2 +} (a q) + 2 e^{-} - - > P b (s) E^{\circ} = - 0.13 V

F e^{2 +} (a q) + 2 e^{-} - - > F e (s) E^{\circ} = - 0.44 V

A l^{3 +} (a q) + 3 e^{-} - - > A l (s) E^{\circ} = - 1.66 V

A l | A l^{3 +} (0.1 M) | | F e^{2 +} (0.2 M) | F e

E_{A l^{3 +} / A l}^{o} = - 1.66

E_{F e^{2 +} / F e}^{o} = - 0.44 V

F e_{(a q)}^{3 +} + e^{-} \to F e_{(a q)}^{2 +}

E^{o} = + 0.77

A l_{(a q)}^{3 +} + 3 e^{-} \to A l_{s}; E^{o} = - 1.66

B r_{2 (a q)} + 2 e^{-} \to 2 B r_{(a q)}^{-}; E^{o} = + 1.66

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