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Question

Given figure shows U-shaped tube with two hands A and B separated by a semi-permeable membrane.
(i) Adding solute to the right side lowers the value of ψs causing water to move to the right side of the tube.
(ii) Applying positive pressure to the left side decreases the value of ψp causing water to move to the right side of the tube,
(iii) applying negative pressure to the left side decreases the value of ψp causing water to move to the right side of the tube.
Which of the given statements is/are true?

886116_a2969d506d1e484c86a3baf0280f6fd9.jpg

A
(i) and (ii)
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B
(i) only
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C
(iii) only
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D
(i), (ii) and (iii)
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Solution

The correct option is B (i) only
According to the given figure, if solute is added to the right side, ψs lowers. This causes water to move to the right side of the tube. When positive pressure is applied to the left side, ψp increases causing water to move to the right side of the tube. Similarly, when negative pressure is applied to the left side, ψp lowers, which causes water to move to the left side of the tube.

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