Given , find the values of x , y , z and w .
The given matrix equation is,
3 [ x y z w ] = [ x 6 − 1 2 w ] + [ 4 x + y z + w 3 ]
Simplify the above matrix equation,
[ 3 x 3 y 3 z 3 w ] = [ x + 4 6 + x + y − 1 + z + w 2 w + 3 ]
Compare both side of above equation,
3 x = x + 4 2 x = 4 x = 2
And,
3 y = 6 + x + y
Substitute the value of x in the above equation,
3 y = 6 + 2 + y 2 y = 8 y = 4
Similarly,
3 w = 2 w + 3 w = 3
And,
3 z = − 1 + z + w 3 z − z = − 1 + 3 2 z = 2 z = 1
Therefore, the value of x is 2 , the value of y is 4 , the value of z is 1 and the value of w is 3.
The given matrix equation is,
Simplify the above matrix equation,
Compare both side of above equation,
And,
Substitute the value of
Similarly,
And,
Therefore, the value of
