Question

Given five different green dyes, four different blue dyes and three different red dyes. The number of combinations of dyes which can be chosen, taking at least one green an one blue dye, is

• A. $3240$
• B. $3570$
• C. $3720$
• D. $3880$

Answer 1

The correct option is C $3720$

$5$ are green

$4$ are blue

$3$ are red

number of ways

=$\left(\right(2{)}^5-1)\times ((2{)}^4-1)\times 2^3=(32-1)(16-1)\times 8=31\times 15\times 8=31\times 120=3720option:C$