Given (i)C(graphite)+O2(g)→CO2(g);△rH∘=xKJmol−1(ii)C(graphite)+12O2(g)→CO(g);△rH∘=yKJmol−1(iii)CO(g)+12O2(g)→CO2(g);△rH∘=zKJmol−1
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
A
z=x+y
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B
x=y−z
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C
x=y+z
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D
y=2z−x
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Solution
The correct option is Cx=y+z (i)C(graphite)+O2(g)→CO2(g)(ii)C(graphite)+12O2(g)→CO(g)(iii)CO(g)+12O2(g)→CO2(g)
On analysis the three given reaction we can see that
by adding (ii) and (iii) we get (i)
(ii) + (iii) = (i)
Thus, the enthalpy of the reaction follows the same.
Addition of enthalpy of (ii) and (iii) will give enthalpy of reaction (i). ∴ y + z = x C(graphite)+O2(g)→CO2(g),i.e.,x=y+z