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Byju's Answer
Standard VII
Mathematics
Equal Angles Subtend Equal Sides
Given : In ...
Question
Given : In
Δ
A
B
C
,
A
C
=
4
x
,
B
C
=
6
x
−
6
,
A
B
=
5
x
−
8
a
n
d
∠
A
=
∠
B
. Find the perimeter of
Δ
A
B
C
.
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Solution
Given,
∠
A
=
∠
B
Hence,
A
C
=
B
C
(Isosceles triangle property)
4
x
=
6
x
−
6
−
2
x
=
−
6
x
=
3
thus,
A
B
=
7
cm,
B
C
=
12
cm,
A
C
=
12
cm
Perimeter =
A
B
+
B
C
+
A
C
=
7
+
12
+
12
=
31
cm
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Similar questions
Q.
In
Δ
A
B
C
,
A
B
=
5
,
B
C
=
6
,
A
C
=
7
,
Δ
P
Q
R
−
Δ
A
B
C
. Perimeter of
Δ
P
Q
R
is
360
. Find PQ, QR and PR.
Q.
In
Δ
A
B
C
,
∠
B
=
90
∘
, Find the sides of the triangle, if
A
B
=
x
c
m
,
B
C
=
(
4
x
+
4
)
c
m
and
A
C
=
(
4
x
+
5
)
c
m
Q.
In
Δ
A
B
C
,
m
∠
B
<
90
and
¯
¯¯¯¯¯¯¯
¯
A
D
⊥
¯
¯¯¯¯¯¯
¯
B
C
. Also
A
B
=
9
,
B
C
=
6
and
B
D
=
2
then find
A
C
.
Q.
In the given figure, a circle touches the side
B
C
of
Δ
A
B
C
at
P
and touches
A
B
and
A
C
produced at
Q
and
R
respectively. If
A
Q
=
5
c
m
, find the perimeter of
Δ
A
B
C
Q.
In ΔABC and PQR, AB=QR, BC=RP, AC=QP. So,
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