Given interchanges: Signs: $+ a n d -$ and numbers 4 and 8

4 \div 8 - 12 = 16

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4 - 8 + 12 = 0

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8 \div 4 - 12 = 24

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8 - 4 \div 12 = 8

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Solution

The correct option is B $4 - 8 + 12 = 0$
On interchanging $+ a n d -$ and 4 and 8 in (b), we get an equation as
$8 + 4 - 12 = 0$ which is true.

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Similar questions

Class-intervals	$0 - 4$	$4 - 8$	$8 - 12$	$12 - 16$	$16 - 20$	$20 - 24$
Frequency	$4$	$7$	$10$	$15$	$11$	$6$

16

Class	0-4	4-8	8-12	12-16	16-20	20-24	24-28	28-32	32-36
Frequency	6	8	17	23	16	15	-	4	3

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4

8

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- a n d \div

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