Given interchanges: Signs: $- a n d \div$ and numbers 4 and 8

6 - 8 \div 4 = - 1

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8 - 6 \div 4 = 1

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4 \div 8 - 2 = 6

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4 - 8 \div 6 = 2

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Solution

The correct option is C $4 \div 8 - 2 = 6$
On interchanging $- a n d \div$ and 4 and 8 in (c), we get the equation as
$8 - 4 \div 2 = 6 o r 8 - 2 = 6 i . e . 6 = 6$ which is true.

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