Question

Given interchanges: Signs: $-and\times$ and numbers 3 and 6

• A. $6-3\times 2=9$
• B. $3-6\times 8=10$
• C. $6\times 3-4=15$
• D. $3\times 6-4=33$

Answer 1

The correct option is B $3-6\times 8=10$

On interchanging $-and\times$ and 3 and 6 in (b), we get the equation as
$6\times 3-8=10$ which is true.