Question

Given, K shell has 2 electrons, L shell has 8 electrons, M shell has 11 electrons, N shell has 2 electrons. The number of electrons present in orbital with $l=2$ is:

• A. $3$
• B. $6$
• C. $5$
• D. $4$

Answer 1

Answer: (A)

$3$

The total number of electrons$=23$. Therefore, the element is Vanadium. The configuration thus,
$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^3$. Electrons with $l=2$ i.e d orbitals$=3$.