Given $l = 28, S = 144$ and there are total $9$ terms. Find $a$ .

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Solution

Given, l = 28.
s = 144 .
n = 9 .
$∴$ Sum of n terms, s = 144
$\Rightarrow \frac{n}{2} (a + l) = 144.$
$\Rightarrow \frac{9}{2} (a + 28) = 144$
$\Rightarrow a + 28 = 144 \times \frac{2}{9}$
$\Rightarrow a = 32 - 28$
$\Rightarrow a = 4$

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Given l=28,S=144 and there are total 9 terms. Find a.

Given, l = 28. s = 144 . n = 9 .∴ Sum of n terms, s = 144⇒n2(a+l)=144.⇒92(a+28)=144⇒a+28=144×29⇒a=32−28⇒a=4

Given $l = 28, S = 144$ and there are total $9$ terms. Find $a$ .

Given, l = 28.
s = 144 .
n = 9 .
$∴$ Sum of n terms, s = 144
$\Rightarrow \frac{n}{2} (a + l) = 144.$
$\Rightarrow \frac{9}{2} (a + 28) = 144$
$\Rightarrow a + 28 = 144 \times \frac{2}{9}$
$\Rightarrow a = 32 - 28$
$\Rightarrow a = 4$