Question

Given ${\log }_{10}2=0.3010$ and ${\log }_{10}3=0.4771$, calculate the values of:
$\log 250$

Answer 1

$\log 250$

$=\log (10\times 5^2)$

$=\log 10+2\log 5$

$=1+2\log \left(\frac{10}{2}\right)$

$=1+2(\log 10-\log 2)$

$=1+2(1-0.3010)$

$=2.398$