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Question

Given log10 25=x, log10 75=y, evaluate without using logarithmic tables, in terms of x, y
(i) log103,
(ii) log102

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Solution

Given that
log1025=x;log1075=y
then
log25=x,log3×25=y
log52=x;log3+log25=y
2log5=x;log3+x=y
log5=x/2;log3=yx[loga×b=loga+logb]
log2=log(105)=log1010log5
log2=1x2
(i) log103=log1000=log250×4=log25+log1010+log4=log52+1+2log2=x+1+2(1x2)
log103=x+1+2x=3
(ii) log102=2log10=2×log1010=2×1=2[log10=1]

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