Question

Given:$\log 2=0.3010$ and $\log 3=0.4771$, find the value of $\log 12$.

Answer 1

Given $\log 2=0.3010$ and $\log 3=0.4771$

$\log 12=\log (4\times 3)$

$=\log 4+\log 3$

$=\log 2^2+\log 3$

$=2\log 2+\log 3$

Substituting the values

$=2\times 0.3010+0.4771$

$=0.602+0.4771$

$=1.0791$