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Byju's Answer
Standard IX
Mathematics
Logarithms
Given log 2...
Question
Given
log
2
and
log
3
, find
log
3
⎷
(
3
2
5
4
√
2
)
.
Open in App
Solution
log
3
⎷
(
3
2
5
4
√
2
)
=
1
3
(
log
3
2
+
log
5
4
−
1
2
log
2
)
=
1
3
(
2
log
3
+
4
log
5
−
1
2
log
2
)
=
1
3
(
2
log
3
+
4
(
1
−
log
2
)
−
1
2
log
2
)
=
1
3
(
2
log
3
−
9
2
log
2
+
4
)
log
2
=
.3010300
,
log
3
=
.4771213
⇒
1
3
(
2
log
3
−
9
2
log
2
+
4
)
=
1.1998692
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