Question

Given $\log 2={}^{.}3010300,\log 3={}^{.}4771213,\log 7={}^{.}8450980,$ find the value of
$\log {}^{.}128.$

Answer 1

$\log \left(.128\right)=\log 128-\log 100=\log \left(2^7\right)-2=7\log 2-2=0.10721$