Question

Given $M=(0,1,2)$ and $N=(1,2,3)$. Find $(N-M)\times (N\cap M)$

• A. {(3, 1), (3, 2)}
• B. {(3, -1), (3, -2)}
• C. {(-3, -1), (-3, 2)}
• D. {(3, -1), (-3, -2)}

Answer 1

The correct option is A {(3, 1), (3, 2)}

$N-M$ means subtracting the common elements of $M$ and $N$ from $N$.
So, $N-M=\left\{3\right\}$
Intersection of two sets has the elements which are common in both the sets.
So, $N\cap M=\{1,2\}$
Cartesian product of two sets is found by forming ordered pairs, where $x$-coordinate is from first set and $y$-coordinate is from second set.
So, $(N-M)\times (N\cap M)=\left\{\right(3,1),(3,2\left)\right\}$.