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Byju's Answer

Standard XII

Physics

Variation of G Due to the Rotation of Earth

Given mA=30...

Question

Given $m_{A} = 30 k g, m_{B} = 10 k g, m_{C} = 20 k g$ . Between $A$ and $B$ $μ_{1} = 0.3$ , between $B$ and $C$ $μ_{2} = 0.2$ and between $C$ and ground $μ_{3} = 0.1$ . The least horizontal force $F$ to start motion of any part of the system of three blocks resting upon one another as shown in figure is $(g = 10 m / s^{2})$

60 N

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90 N

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80 N

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150 N

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Solution

The correct option is A $60 N$
${(f_{s})}_{m a x 1} = μ_{1} m_{A} g s i m i l a r l y, {(f_{s})}_{m a x 2} = μ_{2} (m_{A} + m_{B}) g {(f_{s})}_{m a x 3} = μ_{3} (m_{A} + m_{B} + m_{C}) g {(f_{s})}_{m a x 1} = 0.3 \times 30 \times 10 = 90 N {(f_{s})}_{m a x 2} = 0.2 \times 40 \times 10 = 80 N {(f_{s})}_{m a x 3} = 0.1 \times 60 \times 10 = 60 N$
From all of them ${(f_{s})}_{m a x 3}$ is min
$F_{m i n} = 60 N$
If 60N is applied to the blockC wrt ground it will start moving.

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Similar questions

Q. Given,

m_{A} = 30 kg, m_{B} = 10 kg

and

m_{C} = 20 kg

. The co-efficient of friction between

A

and

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μ_{1} = 0.3

, between

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and

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μ_{2} = 0.2

and between

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μ_{3} = 0.1

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required to start motion of any part of the system of three blocks resting upon the another as shown below is-

Q. Find the least horizontal force P to start motion of any part of the system of the three blocks resting upon one another as shown in Fig. The weights of blocks are A=300 N, B = 100N, and C =200 N. Between A and B, the coefficient of friction is 0.3, between B and C is 0.2, and between C and the ground is 0.1.

Q. Find the least horizontal force

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between A and B,

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Q. Three blocks are connected by strings as shown in figure and pulled by a force

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In the shown figure $m_{A}, m_{B} a n d m_{C}$ are the masses of the three blocks, the incline is frictionless $m_{A} = 5 k g, m_{B} = 10 k g, m_{C} = 2 k g$ . coefficient of friction between A and B is 0.5 and between B and C is 0.1 (Take g = 10 $m / s^{2}$ ) On the basis of above data answer the following questions.

What is the frictional force on block A

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Given mA=30kg,mB=10kg,mC=20kg. Between A and B μ1=0.3, between B and C μ2=0.2 and between C and ground μ3=0.1. The least horizontal force F to start motion of any part of the system of three blocks resting upon one another as shown in figure is (g=10m/s2)

The correct option is A 60 N(fs)max1=μ1mAgsimilarly,(fs)max2=μ2(mA+mB)g(fs)max3=μ3(mA+mB+mC)g(fs)max1=0.3×30×10=90N(fs)max2=0.2×40×10=80N(fs)max3=0.1×60×10=60NFrom all of them (fs)max3 is minFmin=60N If 60N is applied to the blockC wrt ground it will start moving.