Given:
Mass of beaker is X g
Mass of beaker + mixture is Y g
Mass of washed and dried sand is Z g
Find the percentage of sand in the mixture.

\frac{Y - X}{100} \times Z

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\frac{Y - X}{Z} \times 100

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\frac{Z}{Y - X} \times 100

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\frac{100}{Y - X} \times Z

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Solution

The correct option is C $\frac{Z}{Y - X} \times 100$
Mass of mixture= $Y - X$
Percentage of sand= $\frac{w e i g h t o f s a n d}{w e i g h t o f m i x t u r e} \times 100$
= $\frac{Z}{Y - X} \times 100$

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