Given $n_{9} = 28, S = 144$ , and there are total 9 terms. Find a

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Solution

$S = 144 = \frac{9}{2} (a + 28)$
$\Rightarrow 144 \times \frac{2}{9} = 32 = a + 28$
$\Rightarrow a = 32 - 28 = 4$

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Given n9=28,S=144, and there are total 9 terms. Find a

S=144=92(a+28)⇒144×29=32=a+28⇒a=32−28=4

Given $n_{9} = 28, S = 144$ , and there are total 9 terms. Find a

$S = 144 = \frac{9}{2} (a + 28)$
$\Rightarrow 144 \times \frac{2}{9} = 32 = a + 28$
$\Rightarrow a = 32 - 28 = 4$