Given nA - 11- nB - 13- nC - 16- n A- B -3-n B- C -6-n A- C -5 and n A- B- C -2 then the value of n - A- B - C -

The correct option is D 28 We know, n(A∪ B∪ C)= n(A) +n(B) +n(C) n(A∩ B) n(B∩ C) n(C∩ A) + n(A∩ B ∩ C) =11+13+16 3 6 5+2=28 ...

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Given nA = 11...

Question

Given n(A) = 11, n(B) = 13, n(C) = 16, $n (A \cap B) = 3, n (B \cap C) = 6, n (A \cap C) = 5 a n d n (A \cap B \cap C) = 2$ then the value of $n [A \cup B \cup C] =$

24

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27

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28

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Solution

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Similar questions

A, B & C,

n (A \cup B \cup C) = n (A) + n (B) + n (C)

- n (A \cap B) - n (B \cap C) - n (C \cap A)

+ n (A \cap B \cap C)

n (A) = 4, n (B) = 3, n (A \times B \times C) = 24

n (C) =

A, B, C

n (A) = 10, n (B) = 15, n (C) = 20, n (A \cap B) = 8

n (B \cap C) = 9

n (A \cup B \cup C)

\cup

\cup

\cap

\cap

\cap

\cap

\cup

n (A \cup B \cup C) = n (A) + n (B) + n (c) - n (A \cap B) - n (B \cap C) - n (A \cap C) + n (A \cap B \cap C)

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