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Question

Given ¯¯¯a+¯¯b+c+¯¯¯d=0 , which of the following statements is/are not a correct statement?

A
a,b,c and d must be a null vector.
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B
The magnitude of (a+c) equals the magnitude of a(b+d)
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C
The magnitude of a can never be greater than the sum of the magnitudes of b,c and d
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D
b+c must He in the plane of a and d if a and d are not collinear and in the line of a and d, if they are collinear.
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Solution

The correct option is A a,b,c and d must be a null vector.

In order to make vectors a + b + c + d = 0, it is not necessary to have all the four given vectors to be null vectors. There are many other combinations which can give the sum zero.

Simple example:- a=î,b=2î,c=–3î,d=0

(b) Correct
a + b + c + d = 0
a + c = – (b + d)
Taking modulus on both the sides, we get:
| a + c | = | –(b + d)| = | b + d |
Hence, the magnitude of (a + c) is the same as the magnitude of (b + d).

(c) Correct
a + b + c + d = 0
a = – (b + c + d)
Taking modulus both sides, we get:
| a | = | b + c + d |
| a | ≤ | a | + | b | + | c | …. (#)

Equation (#) shows that the magnitude of a is equal to or less than the sum of the magnitudes of b, c, and d.
Hence, the magnitude of vector a can never be greater than the sum of the magnitudes of b, c, and d.

(d) Correct
For a + b + c + d = 0
a + (b + c) + d = 0
The resultant sum of the three vectors a, (b + c), and d can be zero only if (b + c) lie in a plane containing a and d, assuming that these three vectors are represented by the three sides of a triangle.

If a and d are collinear, then it implies that the vector (b + c) is in the line of a and d. This implication holds only then the vector sum of all the vectors will be zero.

This is the explanation of correct solution.


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