CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given P.Q=P×Q and R=P+Q then R is:

A
P2+Q2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
P+Q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
P2+Q2+PQ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[P2+Q2+2PQ]12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B [P2+Q2+2PQ]12
R=P+Q
R=P2+Q2+2PQcosθ
Also since, P.Q=|P×Q|
PQcosθ=PQsinθ
θ=45
R=P2+Q2+2PQ×12 =P2+Q2+2PQ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Operations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon