Given P(A) = and P(B) = . Find P(A or B), if A and B are mutually exclusive events.

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Solution

Let P( A )= 3 5 and P( B )= 1 5 .

For mutually exclusive event Aand B, P( A or B ) can be calculated as,

P( A or B )=P( A )+P( B ) = 3 5 + 1 5 = 4 5

Thus, the value of P( A or B )is 4 5 .

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Similar questions

Given P(A) =and P(B) =. Find P(A or B), if A and B are mutually exclusive events.

Given $P (A) = \frac{3}{5}, P (B) = \frac{1}{5}$ Find P(A or B), If A and B are mutually exclusive events.

P (A / B) = P (B / A)

P (A) = P (B)

(A \cap B) \neq ϕ

P (A / B) = \frac{P (A \cap B)}{P (B)}

P (B / A) = \frac{P (A \cap B)}{P (A)}

P (A) = \frac{3}{5}

P (B) = \frac{1}{5}

P (A or B)

A

B

P (A) = \frac{3}{5}

P (B) = \frac{1}{5}

P (A o r B)

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