Question

Given $P\left(A\right)=\frac{3}{5},P\left(B\right)=\frac{1}{5}$ Find P(A or B), If A and B are mutually exclusive events.

Answer 1

Here P(A) $=\frac{3}{5},P\left(B\right)=\frac{1}{5}$
Since A and B are mutually exclusive events
$\therefore P(A\cup B)=P\left(A\right)+P\left(B\right)$
$\therefore P(A\cup B)=\frac{3}{5}+\frac{1}{5}=\frac{4}{5}.$