Given planes are P1:cy+bz=xP2:az+cx=yP3:bx+ay=zP1,P2 and P3 pass through one line, if
A
a2+b2+c2=ab+bc+ca
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B
a2+b2+c2+2abc=1
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C
a2+b2+c2=1
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D
a2+b2+c2+2ab+2bc+2ca+2abc=1
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Solution
The correct option is Da2+b2+c2+2abc=1 Equation of the planes can be rewritten as follows: −x+cy+bz=0 cx−y+az=0 bx+ay−z=0 If the given three plane intersect in a line, then Δ=∣∣
∣∣−1cbc−1aba−1∣∣
∣∣=0⇒a2+b2+c2+2abc=1