Given reaction is an example of- 7N14 - 0n1 - 6C12 - 1H3-

The correct option is B nuclear fissionThe given nuclear equation _7N^14 + _0n^1 → _6C^12 + _1H^3 is correct and it represents a fission reaction. ...

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Standard XII

Physics

Mass Energy Equivalence

Given reactio...

Question

Given reaction is an example of:
$_{7} N^{14} +_{0} n^{1} \to_{6} C^{12} +_{1} H^{3}$ .

nuclear fusion

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nuclear fission

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radioactive decay

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none of these

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Solution

The correct option is B nuclear fission
The given nuclear equation $_{7} N^{14} +_{0} n^{1} \to_{6} C^{12} +_{1} H^{3}$ is correct and it represents a fission reaction.

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Similar questions

Q. According to the nuclear reaction

_{4} B e +_{2} H e^{4} \to_{6} C^{12} +_{0} n^{1}

, mass number of (Be) atom is

Q. According to the nuclear reaction

_{4} B e +_{2} H e^{4} \to_{6} C^{12} +_{0} n^{1}

, mass number of (Be) atom is

Q. The energy released in the reaction

_{1} H^{2} +_{1} H^{3}

\to_{2} H e^{4} +_{0} n^{1}

- ------- -

mass of

_{0} n^{1} = 1.00867 a m u

mass of

_{1} H^{2} = 2.01410 a m u

mass of

_{1} H^{3} = 3.0160 a m u

mass of

_{2} H e^{4} = 4.0026 a m u

The reaction;

_{4} B e^{9} +_{2} H e^{4} \to_{6} C^{12} +_{0} n^{1}

.
shows the bombardment of Berilium nucleus with a:

_{6}^{14} C \to_{7}^{14} N + X

This nuclear reaction is an example of:

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Given reaction is an example of:7N14+0n1→6C12+1H3.

The correct option is B nuclear fissionThe given nuclear equation 7N14+0n1→6C12+1H3 is correct and it represents a fission reaction.

Given reaction is an example of:
$_{7} N^{14} +_{0} n^{1} \to_{6} C^{12} +_{1} H^{3}$ .

The correct option is B nuclear fission
The given nuclear equation $_{7} N^{14} +_{0} n^{1} \to_{6} C^{12} +_{1} H^{3}$ is correct and it represents a fission reaction.