Given S(s)+O2(g)→SO2(g);ΔH=−298.2kJ SO2(g)+12O2(g)→SO3(g);ΔH=−98.7kJ SO3(g)+H2O(l)→H2SO4(l);ΔH=−130.2kJ H2(g)+12O2(g)→H2O(l);ΔH=−287.3kJ The enthalpy of formation of H2SO4 will be :
A
−814.4kJ
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B
+320.5kJ
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C
−650.3kJ
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D
−933.7kJ
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Solution
The correct option is A−814.4kJ The required thermochemical equation, S(s)+H2(g)+2O2(g)→H2SO4(ℓ) can be written by using (iv)+eqn(i)+eqn(ii)+eqn(iii) Hence, ΔH=−287.3+(−298.2)+(−98.7)+(−130.2) =−814.4kJ