Given set : (256, 64, 16)

(160, 40, 10)

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(144, 36, 9)

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(80, 20, 5)

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(64, 32, 8)

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Solution

The correct option is D (64, 32, 8)
All the numbers in each set can be expressed in terms of power of 2.

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Similar questions

\begin{matrix} 8 & 128 & 2 4 & 1 & 64 . . . . & 32 & 256 \end{matrix}

Class Interval	4−8	8−12	12−16	16−20	20−24	24−28	28−32	32−36	36−40
Frequency	10	12	16	14	10	8	17	5	4

14, 28, 20, 40, 32, 64 ... What number should come next?

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