Given set : (63, 49, 35)

(72, 40,24)

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(72, 48, 24)

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(64, 40, 28)

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(81, 63, 45)

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Solution

The correct option is C (81, 63, 45)
Each set consists of numbers which are obtained by multiplying a certain number by 9, 7 and 5 respectively.
Thus, in the given set, $63 = 7 \times 9, 49 = 7 \times 7, 35 = 7 \times 5$ .
Similarly, $81 = 9 \times 9, 63 = 9 \times 7, 45 = 9 \times 5.$

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Similar questions

7^{2.3} \times 49^{4.7} \times 63^{3.4} \times 81^{5.85} = 63^{?}

56.5

$91$	$49$	$83$	$49$	$76$
$9$	$76$	$x$	$23$	$63$

x

63, 49, 35

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