Given set : (8, 15, 24)

(6, 13, 21)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(10, 17, 28)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(11, 18, 27)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(13, 20, 32)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C (11, 18, 27)
Difference between first two digits should be 7 and last two should be 9 so correct option is C

Suggest Corrections

Similar questions

Q. A sample of 15 data is as follows 17, 18, 17, 17, 13, 18, 5, 5, 6, 7, 8, 9, 20, 17, 3. The mode of the data is

Q. The range of the data:

25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

Q. Show that

\frac{1}{(3 - \sqrt{8})} - \frac{1}{(\sqrt{8} - \sqrt{7})} + \frac{1}{(\sqrt{7} - \sqrt{6})} - \frac{1}{(\sqrt{6} - \sqrt{5})} + \frac{1}{(\sqrt{5} - 2)} = 5

Q. Evaluate

∣ ∣ ∣ ∣ \begin{matrix} 13 & 16 & 19 14 & 17 & 20 15 & 18 & 21 \end{matrix} ∣ ∣ ∣ ∣

Join BYJU'S Learning Program

Given set : (8, 15, 24)

The correct option is C (11, 18, 27)Difference between first two digits should be 7 and last two should be 9 so correct option is C

The correct option is C (11, 18, 27)
Difference between first two digits should be 7 and last two should be 9 so correct option is C