Given Set A = {2, 3, 4, 5} and Set B = {11, 12, 13, 14, 15}, two numb ers are randomly selected one from each set. What is the probability that the sum of the two numbers equals 16?

0.20

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0.25

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0.30

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0.33

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Solution

The correct option is A 0.20
Total ways of selecting one number from each set
$=^{4} C_{1} \times^{5} C_{1} = 20$

Favourable cases are
= {(2, 14), (3, 13), (4, 12), (5, 11)}
= 4

Req. probability $= \frac{fav}{Total} = \frac{4}{20} = 0.2$

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Given Set A = {2, 3, 4, 5} and Set B = {11, 12, 13, 14, 15}, two numb ers are randomly selected one from each set. What is the probability that the sum of the two numbers equals 16?

The correct option is A 0.20Total ways of selecting one number from each set = 4C1× 5C1=20 Favourable cases are = {(2, 14), (3, 13), (4, 12), (5, 11)} = 4 Req. probability =favTotal=420=0.2

The correct option is A 0.20
Total ways of selecting one number from each set
$=^{4} C_{1} \times^{5} C_{1} = 20$

Favourable cases are
= {(2, 14), (3, 13), (4, 12), (5, 11)}
= 4

Req. probability $= \frac{fav}{Total} = \frac{4}{20} = 0.2$