Question

Given - sin^2theta-1/2 sin theta=0 . Find theta

Answer 1

$$\begin{gathered} {\sin }^2\mathrm{\theta }-\frac{1}{2}\sin \mathrm{\theta }=0 \\ \Rightarrow 2{\sin }^2\mathrm{\theta }-\sin \mathrm{\theta }=0 \\ \Rightarrow \sin \mathrm{\theta }\left(2\sin \mathrm{\theta }-1\right)=0 \\ \Rightarrow \sin \mathrm{\theta }=0\mathrm{or}2\sin \mathrm{\theta }-1=0 \\ \Rightarrow \sin \mathrm{\theta }=0\mathrm{or}\sin \mathrm{\theta }=\frac{1}{2} \\ \Rightarrow \sin \mathrm{\theta }=\sin 0°\mathrm{or}\sin \mathrm{\theta }=\sin 30° \\ \Rightarrow \mathrm{\theta }=0°\mathrm{or}\mathrm{\theta }=30° \end{gathered}$$