Question

Given: $\sin A=\frac{3}{5}$, and, $\tan A$ is $\frac{m}{4}$,

m is:

Answer 1

Given $\sin A=\frac{3}{5}$
$\sin A=\frac{P}{B}=\frac{3}{5}$
Thus, $P=3,H=5$
By Pythagoras Theorem,
$H^2=P^2+B^2$
$5^2=3^2+B^2$
$B=4$ cm
Now, $\tan A=\frac{P}{B}=\frac{3}{4}$