Given sinx+cosx = 54. If 1+2sinxcosx=a, find the value of 32a.
We want to find 1+2sinxcosx
where sinx+cosx is given.
By doing some operations we should get 1+2sinxcosx.
We get 2sinxcosx as one term in the expansion of (sinx+cosx)2. This is one of the motivations to consider (sinx+cosx)2.
Also sin2x+cos2x=1
Either way, we have to consider
(sinx+cosx)2.
Then (sinx+cosx)2=(54)2=2516.
⇒sin2x+cos2x+2sinxcosx=2516
⇒1+2sinxcosx=2516=a
⇒32a=32×2516 = 50.