Question

Given slope of $x+3y+5=0$ is $-\frac{1}{3}$

find intercept of y.

• A. $-\frac{5}{3}$
• B. $\frac{4}{3}$
• C. $\frac{2}{3}$
• D. $\frac{5}{3}$

Answer 1

Answer: (A)

$-\frac{5}{3}$

The equation of any straight line can be written as $y=mx+c$, where $m$ is its slope and $c$ is its y - intercept.
$x+3y+5=0$ can be written as $3y=-x-5$ or $y=\frac{-1}{3}x-\frac{5}{3}$
Comparing this equation with the standard form of the equation, we get:
$m=-\frac{1}{3},c=-\frac{5}{3}$
Hence, slope of $x+3y+5=0$ is $-\frac{1}{3}$ and y - intercept is $-\frac{5}{3}$