Given system is accelerated upwards with an acceleration g2 - If M is 10 Kg and pulley and string mass 5kg - The net force acting on the system us -

The correct option is B 45g2 Net force #10;acting on the system is, F #10;= ( M + m)( g + a) #10;= ( 10 + 5)( g + g/2) #10; #10; #10; ...

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Standard XII

Physics

Vector Addition

Given system ...

Question

Given system is accelerated upwards with an acceleration $\frac{g}{2}$ . If $M$ is $10 K g$ and pulley and string mass $5 k g$ . The net force acting on the system us :

\frac{15 g}{2}

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\frac{45 g}{2}

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\frac{55 g}{2}

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\frac{65 g}{2}

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Solution

The correct option is B $\frac{45 g}{2}$
Net force acting on the system is,
$F = (M + m) (g + a)$
$= (10 + 5) (g + \frac{g}{2})$

$= \frac{45}{2} g$

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Given system is accelerated upwards with an acceleration g2 . If M is 10Kg and pulley and string mass 5kg . The net force acting on the system us :

The correct option is B 45g2Net force acting on the system is,F=(M+m)(g+a) =(10+5)(g+g2) =452g

Given system is accelerated upwards with an acceleration $\frac{g}{2}$ . If $M$ is $10 K g$ and pulley and string mass $5 k g$ . The net force acting on the system us :

The correct option is B $\frac{45 g}{2}$
Net force acting on the system is,
$F = (M + m) (g + a)$
$= (10 + 5) (g + \frac{g}{2})$

$= \frac{45}{2} g$