3
You visited us
3
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Property 1
Given t = 2...
Question
Given
t
=
2
π
√
l
g
. If
t
=
1.1
,
g
=
32
and
π
=
√
10
, then the value of
l
is
A
0.463
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.296
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.672
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.968
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is
D
0.968
t
=
2
√
l
g
.....(1)
t
=
1.1
,
g
=
32
a
n
d
π
=
√
10
squaring the first equation (1) we get ,
t
2
=
4
π
2
(
l
g
)
now substitute the values of
t
,
g
a
n
d
π
given above to get
l
l
=
t
2
g
4
π
2
=
1.1
×
1.1
×
32
4
×
10
=
9.68
10
=
.968
Suggest Corrections
0
Similar questions
Q.
Given that:
T
=
2
π
√
l
g
, express
g
in term of
T
,
π
,
a
n
d
l
.
Q.
In the formula
T
=
2
π
√
L
g
,
π
and
g
are constants. If we solve the formula for
L
Q.
If
T
=
2
π
√
l
g
, then relative errors in T and l are in the ratio
Q.
The periodic time
(
T
)
of a simple pendulum of length
(
L
)
is given by
T
=
2
π
√
L
g
. What is the dimensional formula of
T
=
√
g
L
?
Q.
What is the fractional error in g calculated from
T
=
2
π
√
l
/
g
?
Given fraction errors in T and l are
±
x and
±
y respectively.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Property 1
MATHEMATICS
Watch in App
Explore more
Property 1
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app