Given tan -15- what is the value of cosec 2 - 2 -cosec 2 - 2 - -

Given: , We know that: Now we find, Hence the value of is nbsp; ...

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Range of Trigonometric Ratios from 0 to 90 Degrees

Given tan θ=1...

Question

Given $\tan θ = \frac{1}{\sqrt{5}}$ , what is the value of $\frac{{cosec}^{2} θ - \sec^{2} θ}{{cosec}^{2} θ + \sec^{2} θ}$ ?

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\cot θ = \sqrt{3}

\frac{\cos e c^{2} θ + \cot^{2} θ}{{cosec}^{2} θ - \sec^{2} θ}

If \tan θ = \frac{1}{\sqrt{5}}, then write the value of \frac{({cosec}^{2} θ - \sec^{2} θ)}{({cosec}^{2} θ + \sec^{2} θ)} .

tanθ = \frac{1}{\sqrt{7}}

\frac{{cosec}^{2} θ - \sec^{2} θ}{{cosec}^{2} θ + \sec^{2} θ}

s e c^{2} θ + c o s e c^{2} θ = s e c^{2} θ c o s e c^{2} θ

t a n^{2} θ - s i n^{2} θ = t a n^{2} θ s i n^{2} θ

t a n^{2} θ + c o t^{2} θ + 2 = s e c^{2} θ c o s e c^{2} θ

θ

{sec}^{2} θ + {tan}^{2} θ = 2

(c o s e c^{2} θ + {cot}^{2} θ)

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