Given tan - - 1- which of the following is equal to tan -

The correct option is A sin 0^∘ The value of tan θ =1 sin 0^∘ =0 sin 90^∘ =1 cot 45^∘ =1 cos 0^∘ =1 ...

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Standard X

Mathematics

Standard Values of Trigonometric Ratios

Given tan θ...

Question

Given $t a n θ = 1$ , which of the following is equal to tan $θ$ ?

sin 0^{\circ}

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sin 90^{\circ}

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cot 45^{\circ}

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cos 0^{\circ}

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Solution

The correct option is A $sin 0^{\circ}$
The value of $t a n θ = 1$

$s i n 0^{\circ} = 0$
$s i n 90^{\circ} = 1$
$c o t 45^{\circ} = 1$
$c o s 0^{\circ} = 1$

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Similar questions

$sin 90^{\circ} . cos 0^{\circ} + sin 88^{\circ} . cos 2^{\circ} + sin 86^{\circ} . cos 4^{\circ} + . . . . . . . . . . + sin 2^{\circ} . cos 88^{\circ} + sin 0^{\circ} . cos 90^{\circ}$

s i n 90^{\circ} c o s 0^{\circ} + s i n 88^{\circ} c o s 2^{\circ} + s i n 86^{\circ} c o s 4^{\circ} + . . . . . . . . . . . . . . + s i n 2^{\circ} c o s 88^{\circ} + s i n 0^{\circ} c o s 90^{\circ}

θ = t a n^{- 1} (2 t a n^{2} θ) - t a n^{- 1} (\frac{1}{3} t a n θ)

t a n θ

is equal to

Q. lf

θ = {tan}^{- 1} a, ϕ = {tan}^{- 1} b

and

a b = - 1

, then

θ - ϕ

is equal to

$\frac{1 + s i n (90^{\circ} - θ) - {c o s}^{2} (90^{\circ} - θ)}{c o s (90^{\circ} - θ) [1 + s i n (90^{\circ} - θ)]} =$

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Given tanθ=1, which of the following is equal to tan θ?

The correct option is A sin0∘The value of tanθ=1sin0∘=0sin90∘=1cot45∘=1cos0∘=1

Given $t a n θ = 1$ , which of the following is equal to tan $θ$ ?

The correct option is A $sin 0^{\circ}$
The value of $t a n θ = 1$

$s i n 0^{\circ} = 0$
$s i n 90^{\circ} = 1$
$c o t 45^{\circ} = 1$
$c o s 0^{\circ} = 1$