CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given that 0.2^i+0.6^j+a^k is a unit vector. What is the value of a?


A

0.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0.4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

0.6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

0.8

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

0.6


Here, (0.2)2+(0.6)2+a2=1
a2=10.040.36=0.6
a=0.6
Hence, the correct choice is (c).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Unit Vectors
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon