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Question

Given that :

2C(s)+2O2(g)2CO2(g); ΔH=787 kJ

H2(g)+1/2O2(g)H2O(l); ΔH=286 kJ
C2H2(g)+52O2(g)2CO2(g)+H2O(l); ΔH=1310 kJ.
Heat of formation of acetylene is:

A
+1802 KJ
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B
1802 KJ
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C
800 KJ
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D
+237 KJ
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Solution

The correct option is B +1802 KJ
Reversing first two equation and adding upper and then subtract from third equation we get:
C2H2(g)= H2(g) +2C(s)
ΔH=1310KJ(+787KJ+286KJ)
ΔH=1802KJ
but for the formation of C2H2 we have to reverse the equation
So ΔH of reaction also reverse
Therefore ΔH=+1802KJ

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