Given that - 2Cs-2O2g- 2CO2g- - H-787 kJ H2g-1-2O2g- H2Ol- -H -286 kJ C2H2g-5-2O2g- 2CO2g-H2Ol- -H -1310 kJ-Heat of formation of acetylene is-

The correct option is B +1802 KJReversing first two equation and #160;adding upper #160; and then subtract from third equation we get: #160; C_ ...

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Valence Bond Theory

Given that : ...

Question

Given that :
$2 C (s) + 2 O_{2} (g) \to 2 C O_{2} (g)$ ; $Δ H = - 787$ kJ

$H_{2} (g) + 1_{/ 2} O_{2} (g) \to H_{2} O (l)$ ; $Δ$ H $= - 286$ kJ
$C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) \to 2 C O_{2} (g) + H_{2} O (l)$ ; $Δ$ H $= - 1310$ kJ.
Heat of formation of acetylene is:

+ 1802

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- 1802

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- 800

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+ 237

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H_{(a q)}^{+} + O H_{(a q)}^{-} = H_{2} O_{(l)}, Δ H = - X_{1}

m o l^{- 1}

H_{2 (g)} + \frac{1}{2} O_{2 (g)} = H_{2} O_{(l)}, Δ H = X_{2}

m o l^{- 1}

C O_{2 (g)} + H_{2 (g)} = C O_{(g)} + H_{2} O_{(l)} - X_{3}

m o l^{- 1}

C_{2} H_{2 (g)} + \frac{5}{2} O_{2 (g)} = 2 C O_{2 (g)} + H_{2} O_{(l)} + X_{4}

m o l^{- 1}

H_{2} O_{(l)}

2 C (s) + 2 O_{2} (g) \to 2 C O_{2} (g), Δ H = - 787 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l), Δ H = - 286 k J

C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) \to 2 C O_{2} (g) + H_{2} O (l), Δ H = - 1310 k J

2 C (s) + 2 O_{2} (g) ⟶ 2 C O_{2} (g); Δ H = - 787 k J . . . (i)

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J . . . (i i)

C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) ⟶ 2 C O_{2} (g) + 3 H_{2} O (l) . . . . (i i i)

Δ H = - 1301 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l), △ H = - 286 kJ

H_{2} (g) + \frac{1}{2} O_{2} (g), \to H_{2} O (g), △ H = - 245.5 kJ

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l) + x_{1}

k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (g) + x_{2}

k J

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