Given that $2 C l^{-} \to C l_{2} + 2 e^{-}, E^{\circ} = - 1.36 V;$
$H_{2} O \to 2 H^{+} + \frac{1}{2} O_{2} + 2 e^{-}, E^{\circ} = - 1.23 V .$ On electrolysing 1M NaCl solution with inert electrodes, which of the following is correct regarding liberation of electrolytic products ?

Cathode : Na and $H_{2}$

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Cathode : $N a, O_{2}$

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Anode : $O_{2}$

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Anode : $C l_{2}$

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Solution

The correct option is D
Anode : $C l_{2}$

Since $E_{\frac{N a^{+}}{N a}}^{\circ} = - 2.71 V$ < reduction potential of water (=- 0.83V), water will be reduced to $H_{2}$ and $O H^{-}$ at the cathode. Although
$E_{o x}^{\circ} (H_{2} O) = - 1.23 V > E_{\frac{C l^{-}}{C l_{2}}}^{\circ} = (- 1.36 V),$
Water will not be oxidised at the anode due to over potential of oxygen at platinum surface but $C l^{-}$ will oxidised to $C l_{2}$

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Similar questions

Given that $2 C l^{-} \to C l_{2} + 2 e^{-}, E^{\circ} = - 1.36 V;$
$H_{2} O \to 2 H^{+} + \frac{1}{2} O_{2} + 2 e^{-}, E^{\circ} = - 1.23 V .$ On electrolysing 1M NaCl solution with inert electrodes, which of the following is correct regarding liberation of electrolytic products ?

Given are the reactions occuring during the electrolysis of sodium chloride solution:

$2 C l^{-} \to C l_{2} + 2 e^{-}$
$2 H_{2} O + 2 e^{-} \to H_{2} + 2 O H^{-}$

Which of the following is correct regarding liberation of electrolytic products?

Q. A dilute aqueous solution of

N a_{2} S O_{4}

is electrolysed using platinum electrodes. The product at anode and cathode, respectively are:

Identify the correct reaction from the options given below for the electrolysis of $C u C l_{2}$ .

Q. A solution of

N a_{2} S O_{4}

in water is electrolysed using inert electrodes. The products at the cathode and anode respectively, are:

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Given that 2Cl−→Cl2+2e−,E∘=−1.36V; H2O→2H++12O2+2e−,E∘=−1.23V. On electrolysing 1M NaCl solution with inert electrodes, which of the following is correct regarding liberation of electrolytic products ?

Given that $2 C l^{-} \to C l_{2} + 2 e^{-}, E^{\circ} = - 1.36 V;$
$H_{2} O \to 2 H^{+} + \frac{1}{2} O_{2} + 2 e^{-}, E^{\circ} = - 1.23 V .$ On electrolysing 1M NaCl solution with inert electrodes, which of the following is correct regarding liberation of electrolytic products ?