Question

Given that, $a=2,b=0,c=-1$ and $d=-3$, evaluate $\frac{abc-bcd}{acd+abd}$

• A. $-2$
• B. $1$
• C. $0$
• D. $4$

Answer 1

The correct option is C $0$

Since, $a=2,b=0,c=-1$ and $d=-3$

$\therefore \frac{abc-bcd}{acd+abd}$$=$$\frac{\left(2\right)\left(0\right)(-1)-\left(0\right)(-1)(-3)}{\left(2\right)(-1)(-3)+\left(2\right)\left(0\right)(-3)}=\frac{0}{6}=0$