Given that $a^{7} b^{2} c^{3} d^{5} = 512$ . Find the minimum value of $a^{7} + 2 b^{2} + 2 c^{3} + 2 d^{5}$ .

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Solution

The correct option is A 32
Option (a) is the correct answer. Check the video for the approach.

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Similar questions

512 = 8^{3}

3.375 = {1.5}^{3}

\sqrt[3]{512} \times \sqrt[3]{3.375}

a_{i}, i = 1, 2, \dots, n

a_{7} = 9,

a_{1} \cdot a_{2} \cdot a_{7}

K

\begin{matrix} A (7, - 2) \end{matrix} \begin{matrix} B (5, 1) \end{matrix} \begin{matrix} C (3, K) \end{matrix}

a^{7} = 3

\frac{{(a^{- 2})}^{- 3} \times {(a^{3})}^{4} \times {(a^{- 17})}^{- 1}}{a^{7}}

(1 + x)^{15} = C_{0} + C_{1} x + C_{2} x^{2} + . . . . . C_{15} x^{15},

C_{2} + 2 C_{3} + 3 C_{4} + . . . . . 14 C_{15}

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