Given that a and d are the first term and the common difference of an A.P (where a>0),the relation between a and d that satisfies the relation $(y / z) - (a / y) = (1 / 2)$ where y and z are second and third terms of an A.P. is

a = -d

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a = 3d

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a = 4d

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a = -3d

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Solution

The correct option is D
a = -3d

$y = a + d z = a + 2 d (a + d) / (a + 2 d) - a / (a + d) = (1 / 2)$

Solving we get a = - 3d

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Given that a and d are the first term and the common difference of an A.P (where a>0),the relation between a and d that satisfies the relation (y/z)−(a/y)=(1/2) where y and z are second and third terms of an A.P. is

The correct option is D a = -3d y=a+dz=a+2d(a+d)/(a+2d)−a/(a+d)=(1/2) Solving we get a = - 3d

Given that a and d are the first term and the common difference of an A.P (where a>0),the relation between a and d that satisfies the relation $(y / z) - (a / y) = (1 / 2)$ where y and z are second and third terms of an A.P. is

The correct option is D
a = -3d

$y = a + d z = a + 2 d (a + d) / (a + 2 d) - a / (a + d) = (1 / 2)$

Solving we get a = - 3d