Given that a, b and c are three consecutive multiples of 5('a' being the smallest). Choose the correct option.

a + b + c = 15

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b = a + 5

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c = b + 5

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a = c - 10

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Solution

The correct options are
B
b = a + 5

C
c = b + 5

D
a = c - 10

The consecutive multiples of '5' differ by 5.
So, b = a + 5
c = b + 5
c = a + 5 + 5
c = a + 10
a = c - 10

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Similar questions

Given that a, b and c are three consecutive multiples of 5. Choose the correct option.

If $a$ , $b$ and $c$ are three consecutive multiples of $5$ then,

a, b, c > 0

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\frac{n [(A \cap B) \times (A \cap C)]}{n [(B \cap C) \times (A \cap B \cap C)]}

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a < b < c < d

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