Question

Given that $a,b,c,d,p$ and $q$ are natural numbers such that $a<b$ and $d<c$. It is also given that the following result holds true:

$\frac{a}{b}\times \frac{d}{c}=\frac{q}{p}$

Choose the correct option(s):

• A.
• B.
• C. q > p
• D. q < p

Answer 1

Answer: (A), (D)

The correct options are
A

D

q < p

$\frac{a}{b}\times \frac{d}{c}=\frac{q}{p}$
here, $\frac{a}{b}>\frac{q}{p}$ and $\frac{d}{c}>\frac{q}{p}$ and $q<p$
For eg,
$\frac{2}{3}\times \frac{5}{6}=\frac{10}{18}$
here, $\frac{2}{3}>\frac{10}{18}(as\frac{12}{18}>\frac{10}{18})$
and $\frac{5}{6}>\frac{10}{18}(as\frac{15}{18}>\frac{10}{18})$
also, $10<18$